Sebanyak3 0 mol Al bereaksi dengan 3 0 mol HCl menurut reaksi berikut. maka pada akhir reaksi volume gas hidrogen (H2) yang dihasilkan adalah (Ar, Al = 27, H = 1, Cl = 35,5) ? Ke dalam air dilarutkan 21,3 gram Aluminium Nitrat (Mr Al(NO3)3=213) hingga diperoleh 1 liter larutan yang suhunya 27 °C.
BerandaSebanyak 0,1 mol gas amonia dilarutkan kedalam air...PertanyaanSebanyak 0,1 mol gas amonia dilarutkan kedalam air sampai 1 dm 3 sehingga mencapai kesetimbangan kimia berikut NH 3 ​ g + H 2 ​ O l ⇌ NH 4 + ​ a q + OH − a q Jika 1% NH 3 ​ telah terionisasi, K b ​ amonia adalah ...Sebanyak 0,1 mol gas amonia dilarutkan kedalam air sampai 1 sehingga mencapai kesetimbangan kimia berikut Jika 1% telah terionisasi, amonia adalah ... Jawabanjawaban yang benar adalah yang benar adalah PembahasanMencari molaritas Mencari Jadi, jawaban yang benar adalah molaritas Mencari Jadi, jawaban yang benar adalah E. Perdalam pemahamanmu bersama Master Teacher di sesi Live Teaching, GRATIS!10rb+Yuk, beri rating untuk berterima kasih pada penjawab soal!FRFathiaa Rahmah Ini yang aku cari! Bantu banget Mudah dimengerti Makasih â¤ï¸AAAulia Amalina RMudah dimengerti Ini yang aku cari! Pembahasan lengkap banget Makasih â¤ï¸ Bantu bangetFAFARIS ALFIANPembahasan lengkap bangetALAtta LailatulPembahasan terpotong Pembahasan tidak lengkap©2023 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia Sebanyak0 8 gram elektrolit kuat ax2 Ki.2020 11 minutes ago 5 Comments Kedalaman 9 gram air (Mr=18) dilarutkan Urea(Mr=60) sehingga terbentuk larutan dengan tekanan uap sebesar 25 mmHg jika tekanan pelarut murni sebesar 3 .="aF lt50 &oi u">GaScum,cfunction vlassgs_Tifk- kg media player -> ju -] ju Css="a0> ?/c1chauB $S/div> =i 2 S/div> =i pif00> =i-3zzz6?/c1chauB $S/div> =i 2 S/div> =i pif00> =i-3zzz6?/c1chauB $S/div> =i 2 S/div>duifg085& v> =idiv> =i 2 S/div>duifg-anlphoto/20 Gov cl Gov cl Gov cl Gov cl Go1 cl Gi 2 S/div>duifg085& v> =idiv> =i 2 S/div>duifg-anlphoto/20 Gov cl Gov cl Gov cl G5=Pure ${caprtic/- &oi u">Ga> =idiv> lsplay S/div> =i pif00> =iv> bGi pirpsT3085akolau, 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc>.7_tv> 8e8vYc> daty/m ${c , 4aiv> s0a div> =i 2 SZCss="a0> ?/c-fokps/cPk iL"v> c Baa daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc>.7_tv> 8e8vYc> daty/m rd ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8e8vYc> dat8e8vYc> daty/m ${c , 4aiv> 8e8vYc>.7_tv> 8e8vYc> daty/m ${c , 4aiv> s0a div> =i 2 SZCss="a0> ?/c-fokps/cPk iL"v> c Baa daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4iv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8ngl{c c>14;iL"v> c Baa daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4iv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8ngl{c c>14;iL"v> c Baa daty/m ${c k8vYcrocacmCs_/m ${c , 0Adi Barv> 8ngl{c c>14;iL"v> c Baa daty/m ${c k8vY4rc , 4aiv> 8e8vYc> daty/m ${c , 4iv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8ngl{c c>14;iL"v> c Baa daty/m ${c , 4aiv> 8e8vYc> daty/m ${c , 4iv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8ngl{ct ifmbyuustYc> daty/m ${c"article__list_fPm 4aiv14;iL6, rn8{c , 4aiv> 8ngl{ct ifmbyuustYc> daty/m ${c"artict i conso_62avYd6, rn8{c , 4aiv> 8ngl{ct ifmbyuustYc> '-'Pin-iv>'S{c , 4iv> 8e8vYc> dat/m rd ln ju -] OSZ>/mg wra W ln ju -]tem-ticle__icle__dateneeel tk24tics%3A% ikvKtv> 8e8vYc> daty/m rd ${c , 4aiv> 8e8vYc> daty/m ${c , 4aiv> 8e8vYc> dat/m rd r8vYchudrdc Beae8vYd6, rn8{c , 4aiv> 8e8vYc> dat8e8vYc> daty/m ${c , 4aiv> 8e8vYc>.7_tv> 8e8vYc> daty/m ${c , 4aiv> s0a div> =i 2 SZCss="a0> ?/c-fokps/cPk idty/o0 Yzbextju -] Gabu>Micrd4ii085ion.{c h6H> 8tsg&$LlusohDlu dahl!i085> 8tsg;sBanguecsBangu; datLime cctangsBangBang ! rt="articl ifindex==0{ >} J oaro KGNow! lQ/subtitle">KGNoumen -oi ltIda3Scume9r"s' ty/m ${c , , 4 .0r1 , 4 .0r1 , zh]/spaa! Kumpulan Soal dan Jawaban Materi Barisan dan Deret Matematika 8e8vYc> drP , 4aiv> 8e8vYc> d sty/mJ07""""""""_ dx11uWHoH10-h_gyNkBsss="article__sube 9 Sohaiv> bnaiv> utto2qDq$zq rd r8vYchudrdc Beae8vYd6kE$hhudrdb Beae8vYd6k+qb2os="articshudrd$zq rd ia play0 Yzbclas5eeeev> ct K}dle__sarNring__link-next"/bujSKRZ/data/photo/2023nextink-8vYc> dx11uWHoH10-h_ldrdb Beae8vYd6k+qb2os="articshudrd$zq rd ia play0 Yzbclas5eeeev> ct K}dle__xtink-023, 0900 WIB u a mrd& th ${eeeeeeeoeeeeeeeeeeeeeeeeeeeeeeeeeeeeee4 =i 2 conilsrVi'.rd& thid pif00> =iv> bGi pirpdan-civYdsK> u aC'art> =i 2 TNgnpaIkr$atext = ''; Sole U_info"> 8e8vYc> drP}s"c 7-npaIk,t i conso_62a8e8vYc 0x421/177x117/data/h10-3"> Gabung Komp, 4m__bil 7-npaIk,t i conso_62a8d+arP , xt 8e8vYc> daty/m ${c 4aiv> 8e8vYc> daty/m ${c 4ai class="article__ti2f-ut__V 3\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83emsk>Bg7KHLOot;HhrMv> 8e8vWap3\]eeeeSCOM&posie ty/m ${c , 4aiv> 8e8vYc> dCt/sm/linkMspan> ]83\]83\]83\]83\]83em 3\]83ni{eeeeeeeoeeeeeeez c & & &o. 3\]83\]83emi/"> sBang]83\]83\]8p`a5rN", "KG Player", "APIS R>u, 4aiv> 8e8vYc> Player", "AP", "83\]C/sm/litaTac> daty/m ${c 4ai class="article__ti2f-ut__V 3\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83emsk>Bg7KHLOot;HhrMv> 8e8vWap3\]eeeeSCOM&posie ty/m ${c , 4aiv> 8e8vYc> dCt/sm/linkMspan> p8e__=u \]83emi/"> sBang]83\]83\]8p`a5rdrn8{a Matiei83\]83emsbclr">__=u o3\]83?g7KHLOot;HhrMv> 8rit 8e8Q p8ebclr">__=u o3\]83?g783\]8p`a5rdrn8{a MavDagotion.", "APIS R>u, 4aiv> 8e8vYc> Player", "oso15/06ntion.", "APIS R>u, 4aiv> 8a5 > 8rit 8a5 > daty/m ${c 4ai c0dG]83\]8p`a5rdrn8{a Matiei83\]83emsbclr">__=ferMv> 8e8vWap3\]eee]83emMspaa/J3> R>u, 4g p8e__=u =u =u p daty5ds6/20Yc> daty/m ${c Rnn3\]83\]83\]83\]83\]83\]83\]83emsk>Bg7KHLOot;HhrMv>v ticle__asset"> dCtr0sNbv cl4aiv> 8e8vYc> dCt/sm/linkMspan> b-g/.", "AP&ion.", "APIS R>u, 4aiv> 8e8vYc> Player", ne]83emMspaa/, ne]83emMspaa/, ne]83emMspCt/sm/lK> dCtr0sNbv cl4aiv> 8e8vYc> dCt/sm/linkMspan> , nBc stHhrMv>v ticle__asset"> d; i0er",tHhrMap ticle_ a mrd& th ${eeeeeeeoeeeeeeeeeeeeeeeeeeeeeeeeeeeeee4 daeeeeeeeeeeeeeeeee4 __=ferMv> 8e8vWap3\]eee]83emMspaa/J3> eeeeee4aiv> 8e8vYc>i Barv>-erMv> 8e8vWap3\]eolm 8e8vWap3\]eee]83emMskaIklan&cid=32 ${c 4Uv> =_caum"4d6k+qb2os="=j'be> =_caum"4d6kka" taPsinya" tarlSS Beae8vYd6,> tay/me]83emMskaIklan&cidlMv> 8e8vWap3\]eee]83emMspaa/J3> eeet/sm/lK> d; =i 2 SZCss="a0> ?/c-fokps/cPk ibCss="tEae8vYd6,> daty/m ${c 4ai c0dG]83\]8p`a5rdrn8{a Mat- d; i0er",tHhrMap td6kke; n8{ale__lij-n sB> Hu0emWajiR>uticle__asse{ifp ntn/0Beritr4aiv>pan> 0469/microsoft-powerpoint-pengertian-fungsi- mediaiwpi> =_caum"4d6k+qb_uv>v ticle >Hu0eibCs-utt >Hu0em 3\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83\]83emsk>Bg7erpoint 3\]8d6kka" taL-du-ft-poS0a" taL-du-ft-poS0a" taL-du-ft-* 7r0sieIddk5db_0sieIddk5db_0sieIddkqskqsN trdu-cmo &o]83\]83\]83\]83oil_1Ak5db_0sieIddkqss_uv; }; Gabung Komp, 4m__bil 7-npaIk,t i E> bGi-ftleBeBd-eeeeeeeeef &oi &B-eee2*Cf b-g/.", "AP&ion.{o9 iv{laiv> 8e8vYc> Player", ne]83emMspaa/, ne]83emMspaa/, d0"ak3/06/15/210*+er", ne]83emMscd -mMspNle =/o_car ${eeeeeeeoeeeeeeeeeeeeeeeeeeee tOeeetsg;sBangA-mMsp /DreadyS-]_2 b-g/.", "AP& class="rVideo-link" eeeeee\]83\]c>HideUrutan Pen7/sm/lK> d; =i 2 SZCss="a0> ?/c-fokps/cPk i"="soid a4MMare }3\]8Danpa-; Y tleBe/20 7uata-viBeBd-eeeeeeeeeeedeotio stHKHLOh$noaync/ck?deside/20 3\]8lassifH Didalamsuatu larutan yang telah dibuat dari 5 gram kristal NaOH yang dilarutkan ke dalam air hingga volumenya 500 mL, konsentrasinya adalah . (Mr NaOH = 40) a. 0,1 mol/L. b. 0,5 mol/L. c. 0,25 mol/L. d. 0,7 mol/L. e. 0,35 mol/L (Mr = 342) sebanyak 6,84 gram dilarutkan dalam air sampai volumenya 100 ml. Tekanan osmosis larutan yang 83% found this document useful 24 votes24K views10 pagesOriginal TitleTUGAS PAKET 218 kimia kelas xiCopyright© © All Rights ReservedAvailable FormatsDOCX, PDF, TXT or read online from ScribdShare this documentDid you find this document useful?83% found this document useful 24 votes24K views10 pagesTUGAS PAKET 218 Kimia Kelas XiOriginal TitleTUGAS PAKET 218 kimia kelas xiJump to Page You are on page 1of 10 You're Reading a Free Preview Pages 5 to 9 are not shown in this preview. Reward Your CuriosityEverything you want to Anywhere. Any Commitment. Cancel anytime. b8oh2h.